Answer to Question #309727 in Electricity and Magnetism for Wendell

Question #309727

A particle with a charge of 5nC has a distance of 0.5m away from a charge of 9.5nC. What is its electric potential energy?

1
Expert's answer
2022-03-11T08:27:53-0500

Answer

electric potential energy is given by

U=kqqr=910951099.51090.5=85.5108JU =\frac{kqq'}{r}\\=\frac{9*10^9*5*10^{-9}*9.5*10^{-9}}{0.5}\\=85.5*10^{-8}J



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