Answer to Question #308285 in Electricity and Magnetism for yengg

Question

What is the electric field strength at a point 40 cm from a charge of 5x10⁹ C?

Answer 1

Electric field

$E=\frac{kq}{r^2}$

Put value

$$E=\frac{9\times10^9\times5\times10^9}{0.4^2}=2.82\times10^{20}N/C$$