2 charged particles reacted with a force of 0.31 N with a distance of 1.5 cm, the 2nd charge contains 54 nC. Find the value of the first charge
Answer
First charge is
"Q=\\frac{Fr^2}{kQ'}"
"Q=\\frac{0.31*0.015*0.015}{9*10^9*54*10^{-9}}\\\\=0.14\\mu C"
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