Find the electric force between two electrons separated by a distance of 10 cm.(The charge of an electron=-1.6x10^-19 C
Answer
the electric force between two electrons separated by a distance of 10 cm is given by
F=kqq′r2=9∗109∗1.6∗1.6∗10−380.1∗0.1=23.04∗10−27NF=\frac{kqq'}{r^2}\\=\frac{9*10^9*1.6*1.6*10^{-38}}{0.1*0.1}\\=23.04*10^{-27}NF=r2kqq′=0.1∗0.19∗109∗1.6∗1.6∗10−38=23.04∗10−27N
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