Question #303474

Two point charges are placed as follows: charge q1 = -1.50 nC is at y = +6.00 m and charge

q2 = +3.20 nC is at the origin. What is the total force (magnitude and direction) exerted by

these two charges on a negative point charge q3 = -5.00 nC located at (2.00 m, -4.00 m)?



1
Expert's answer
2022-03-01T17:33:18-0500

F=kq3(q1r12+q2r22)=8.3 nN,F=kq_3(\frac{q_1}{r_1^2}+\frac{q_2}{r_2^2})=8.3~nN,

α=32°.\alpha=32°.


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