Answer to Question #303043 in Electricity and Magnetism for Happpy

Question

Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electric field falls off as  1/r^2 of the distance r from the charge. How does the surface area change with r?

a.1/r

b.1/r^2

c.r^2

d.ln r

Answer 1

Answer

Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electric field falls off as 1/r^2 of the distance r from the charge. does the surface area change with square of r.