A monochromatic light ray with the wavelengths of 600nm disperses in glass with a refractive index of 1.5. Find the wavelength of the light ray in the glass
We know that
λ=600nmμ=1,μ′=1.5\lambda=600nm\\\mu=1,\mu'=1.5λ=600nmμ=1,μ′=1.5
λα1μ\lambda\alpha\frac{1}{\mu}λαμ1
Now
λλ′=μ′μ\frac{\lambda}{\lambda'}=\frac{\mu'}{\mu}λ′λ=μμ′
λ′=μμ′×λ\lambda'=\frac{\mu}{\mu'}\times\lambdaλ′=μ′μ×λ
λ′=600×10−9×11.5=400nm\lambda'=600\times10^{-9}\times\frac{1}{1.5}=400nmλ′=600×10−9×1.51=400nm
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