Question

A proton moving with a velocity of 3 × 10^8 ms-1 perpendicularly in a magnetic field strength X T. Given that the force of the proton received is 4.8 × 10^-13 N. Find the value of X.

Answer 1

$F=qvB,\implies$

$B=\frac F{qv}=0.01~T.$