Question

What are the magnitude and direction of the electric field that will balance the

weight of (a) an electron and (b) a proton?

Answer 1

$qE=mg,\implies E=\frac{mg}q,$

a)

$E_1=\frac{m_1g}{q_1}=-5.58\cdot 10^{-11}~\frac NC,$

b)

$E_2=\frac{m_2g}{q_2}=1.02\cdot 10^{-7}~\frac NC.$