Question

1. A proton (q=+5x10^-19C) is injected from right to left into a field B of 0.5 T directed toward the upper side of a sheet of paper. If the velocity of the proton is of 4x10⁶m/s, find the magnitude and direction of the magnetic force over the proton.

Answer 1

F=Force

q=charge

v=velocity

B=magnetic field

θ= angle between the particle and the magnetic field=90

Then:

$F=qvBsin\theta$

$F= 5×10^{-19}×4×10^6×0.5 sin90$

$F=1×10^{-12}\>N$