Answer to Question #256793 in Electricity and Magnetism for SFRM21

Question #256793

Calculate the potential energy of a charge +6nC placed at 0.07m from a charge +76 x10-6C. If the same charge(+6nC) is now at 0.07m from a charge -88 x10-6C, find its new potential energy.   



1
Expert's answer
2021-10-26T17:21:48-0400

Now we know that

Potential energy

U=kq1q2rU=\frac{kq_1 q_2}{r}


U=9×109×6×109×76×1060.07=0.05862JU=\frac{9\times10^9\times6\times10^{-9}\times76\times10^{-6}}{0.07}=0.05862J

U=9×109×6×109×88×1060.07=0.0678JU=-\frac{9\times10^9\times6\times10^{-9}\times88\times10^{-6}}{0.07}=-0.0678J


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