what is the magnitude of the electric field at a point midway between a-6.5uC and +5.4uC charge 8.0cm apart ? assume no other charge nearby . express your answer using two significant figures.
E=kQ1r12+kQ2r22E=9×109×(−6.5×10−6)0.042−9×109×5.4×10−60.042=6.7×107 N/CE = \frac{kQ_1}{r_1^2} + \frac{kQ_2}{r^2_2} \\ E = \frac{9 \times 10^9 \times (-6.5 \times 10^{-6})}{0.04^2} - \frac{9 \times 10^9 \times 5.4 \times 10^{-6}}{0.04^2} \\ = 6.7 \times 10^7 \;N/CE=r12kQ1+r22kQ2E=0.0429×109×(−6.5×10−6)−0.0429×109×5.4×10−6=6.7×107N/C
In negative x direction
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