Question

what is a magnitude of the electric field at a point midway between a -6,5uC and +5.4uC charge 8.0cm apart?

Answer 1

$E_1=\frac{kq_1}{r^2}\\E_1=\frac{{k}\times{(-6.5\times10^{-6})}}{4^2\times10^{-4}}$

$E_1=-3.656\times10^7N/c$

$E_2=\frac{kq_2}{r^2}\\E_2=\frac{{k}\times{(5.4\times10^{-6})}}{4^2\times10^{-4}}$

$E_2=3.037\times10^7N/c$

$E=|E_1|+|E_2|$

$E=6.693\times10^{7}N/c$