Question #230788

Using Maxwell’s equations in free space, derive the wave equation for the

y-component of the electric field vector.


Expert's answer

Maxwell’s equations in free space are given by

∇⋅E=0∇⋅B=0\nabla\cdot {\bf E}=0\\ \nabla\cdot {\bf B}=0∇×E=−1c∂B∂t\nabla\times {\bf E}=-\frac{1}{c}\frac{\partial {\bf B}}{\partial t}∇×B=1c∂E∂t\nabla\times {\bf B}=\frac{1}{c}\frac{\partial {\bf E}}{\partial t}

The last two equations give

∇×∂B∂t=1c∂2E∂t2\nabla\times \frac{\partial{\bf B}}{\partial t}=\frac{1}{c}\frac{\partial^2 {\bf E}}{\partial t^2}

−c∇×∇×E=1c∂2E∂t2-c\nabla\times \nabla\times {\bf E}=\frac{1}{c}\frac{\partial^2 {\bf E}}{\partial t^2}

or


∇×∇×E=−1c2∂2E∂t2\nabla\times \nabla\times {\bf E}=-\frac{1}{c^2}\frac{\partial^2 {\bf E}}{\partial t^2}

Using identity

∇×∇×E=∇(∇⋅E)−∇2E\nabla\times \nabla\times {\bf E}=\nabla(\nabla\cdot {\bf E})-\nabla^2{\bf E}

and first Maxwell’s equation, we obtain

∇×∇×E=−∇2E=−1c2∂2E∂t2\nabla\times \nabla\times {\bf E}=-\nabla^2{\bf E}=-\frac{1}{c^2}\frac{\partial^2 {\bf E}}{\partial t^2}

Finally

∇2E−1c2∂2E∂t2=0\nabla^2{\bf E}-\frac{1}{c^2}\frac{\partial^2 {\bf E}}{\partial t^2}=0

Also we have

∇2Ey−1c2∂2Ey∂t2=0\nabla^2E_y-\frac{1}{c^2}\frac{\partial^2 E_y}{\partial t^2}=0


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