Seawater has epsilon r = 80. Its permittivity is
(a) 81
(b) 79
(c) 5.162 x 10^-10 F/m
(d) 7.074 x 10^-10 F/m
Gives
ϵ0=8.85×10−12c2/Nm2\epsilon_0=8.85\times10^{-12}c^2/Nm^2ϵ0=8.85×10−12c2/Nm2
ϵr=80\epsilon_r=80ϵr=80
We know that
ϵ=ϵ0ϵr\epsilon=\epsilon_0\epsilon_rϵ=ϵ0ϵr
Option (D) is correct option
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