Answer to Question #213076 in Electricity and Magnetism for Natasha

Question

An object 6 cm high is located in front of a convex spherical mirror of radius 40 cm. Determine the position and the nature of the image.

Answer 1

Gives

u=-6cm

v=?

$f=-\frac{r}{2}=-\frac{40}{2}=-20cm$

We know that

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

$-\frac{1}{20}=-\frac{1}{6}+\frac{1}{v}$

$\frac{1}{6}-\frac{1}{20}=\frac{1}{v}$

$\frac{20-6}{120}=\frac{1}{v}$

$\frac{14}{120}=\frac{1}{v}$

$v=\frac{120}{14}=\frac{60}{7}=8.5cm$

$m=-\frac{v}{u}=-\frac{8.5}{-6}=1.42$

Image is virtual