Question #211976

An electric potential field is produced by point charges 1 mC and 4 mC located at (-2,1,5) and 52 and (1,3,1) respectively. The energy stored in the field is


Expert's answer

Given,

Point charge (q1)=1mC(q_1)=1mC

q2=4mCq_2=4mC

Let co-ordinates be P and B are (-2,1,5) and (1,3,1)

r1=−2i^+j^+5k^r_1=-2\hat{i}+\hat{j}+5\hat{k}

r2=i^+3j^+k^r_2=\hat{i}+3\hat{j}+\hat{k}

⇒d→=r2−r1\Rightarrow \overrightarrow{d}=r_2 - r_1

⇒d→=i^+3j^+k^+2i^−j^−5k^\Rightarrow \overrightarrow{d}=\hat{i}+3\hat{j}+\hat{k} +2\hat{i}-\hat{j}-5\hat{k}

⇒d→=3i^+2j^−4k^\Rightarrow \overrightarrow{d}=3\hat{i}+2\hat{j}-4\hat{k}


∣d∣=32+22+42|d|=\sqrt{3^2+2^2+4^2}


=9+4+16=\sqrt{9+4+16}


=29=\sqrt{29}

Hence, the required stored energy,


U=q1q24πϵod2U=\frac{q_1q_2}{4\pi \epsilon_o d^2}


Now, substituting the values,


⇒U=9×109×1×10−3×4×10−329\Rightarrow U = \frac{9\times 10^9\times1\times 10^{-3}\times 4\times 10^{-3}}{29}


⇒U=1.24×103J\Rightarrow U = 1.24\times 10^{3}J


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