A thin glass rod is bent into a semi circle of radius R a charge Q is uniformly distributed along the upper-half and a charge −Q is uniformly distributed along the lower-half. Find the electric field E~ at the center of the semicircle.
The semi circle should look like the one shown below
considering the center P of the semicircle, and taking two elements of width the magnitude of the field at P is;
field at x due to pair of electrons
Comments
Leave a comment