A 72 nC charge is located at x = 3.00 m on the x-axis and an 8.0 nC charge is located at x = 7.0 m. At what point on the x-axis is the electric field zero?
Since the charges are the same sign, the point where Ex = 0 is clearly between them and closer to the 8.0 nC charge. The condition for
"E_x =0 \\\\\n\n\\frac{kq_1}{(x-x_1)^2} = \\frac{kq_2}{(x_2-x)^2} \\\\\n\n\\sqrt{ \\frac{q_1}{q_2} } = 3 \\\\\n\n3(x_2-x) = x-x_1 \\\\\n\n3(7 -x)=x-3 \\\\\n\n21 -3x=x -3 \\\\\n\n4x=24 \\\\\n\nx=6 \\;m"
Comments
Leave a comment