A particular hydrogen atom is in an energy state with E = –2.418×10-19 J. Calculate the maximum angular momentum this atom could have.
Give the value as a multiple of ℏ to 2 decimal places. (e.g. if you calculated L = 1.41ℏ, then you would enter "1.41" as your value).
"E=\\frac{E_0}{n^2},\\implies"
"n=\\sqrt{\\frac{E_0}{E}}=\\sqrt{\\frac{13.6}{2.418}}=2.37,"
"L_e=\\hbar \\sqrt{n(n+1)}=28.26\\hbar."
Comments
Leave a comment