Answer to Question #191257 in Electricity and Magnetism for Computer On The Go

Question

Calculate the work required to bring a charge of 5.0 statC from a point of 24 cm from a charge of 60 statC to a point 3 cm from it.

Answer 1

Gives

$q_1=5statC$

$q_2=60statC$

$r_1=24cm$

$r_2=3cm$

Point charge=q₀

$W=q(V_2-V_1)\rightarrow(1)$

$V_2=\frac{kq}{r_2^2}$

$V_1=\frac{kq}{r_1^2}$

$V_1=\frac{9\times10^9\times5\times3.33\times10^{-10}}{24\times10^{-2}}$

$V_1=62.54V$

$V_2=\frac{9\times10^9\times60\times3.33\times10^{-10}}{3\times10^{-2}}$

$V_2=$ 5994 V

Put value in eqution (1)

$W=q_0(5994-62.5425)$

$W=5931.45J$