Answer to Question #186327 in Electricity and Magnetism for Aida

Question

A charge q = 1μC moves with velocity v = 3.0m/s in a direction which forms an angle of 45 degrees with respect to a magnetic field B = 0.15T .

Compute the intensity and the direction of the force acting on the charge.

Answer 1

$F=qvB\sin \alpha,$

$F=10^{-9}\cdot 3\cdot 0.15\cdot 0.71=0.32~\mu N.$