Answer to Question #185629 in Electricity and Magnetism for Aida

Question

A charged particle is moving without deflection in a space region where an elec- tric field E = 3.5x102V/m and a magnetic field B = 0.25T act in perpendicular directions.

Calculate the speed of the particle.

Answer 1

To be given in question

Electric field (E)=$3.5\times10^2volt/meter$

Magnetic field(B)=0.25tesla

To be asked in question

Speed of particle=?

We know that

$E=B\times v$

$E=Bvsin\theta\rightarrow(1)$

Eqution (1)put values

$3.5\times10^2=0.25\times v\times sin90°$

$v=\frac{3.5\times 10^2}{0.25}=1400meter/sec$

$v=1.4\times10^3 meter/sec$