A conductive wire 23.5cm long is dipped in a magnetic field B, which is per- pendicular to the wire. A current i = 3.5A travels the wire and a force F = 2.2 · 10−4N acts on it.
Compute the value of the magnetic field B.
The circled dots indicate that the magnetic field is exiting from the plane of the paper
Answer
Force is given by
F=lLBsin"\\theta"
So magnetic field is given
"B=\\frac{F}{lLsin\\theta}\\\\=\\frac{2.2\\times10^{-4}}{3.5\\times 0.235\\times sin90\u00b0}\\\\=2.67\\times10^{-4}T"
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