Answer to Question #180857 in Electricity and Magnetism for passout

Question

Calculate the value of α, β, γ ,η for a rubber at a frequency f=106 Hz. It is given that εr = 3.5, σ=10-16 mhos/m & µr=1.   

Answer 1

$\alpha=\sqrt{\pi f \mu_0 \sigma}=2\cdot 10^{-10}~\frac{Np}{m}.$

$\beta=\frac{2\pi\sqrt{\epsilon_r}}{c}=4.1\cdot 10^{-10}~\frac{rad}{m}.$

$\eta=120\pi~\Omega,$

$\eta_1=\frac{\eta}{\sqrt{\epsilon_r}}=64\pi~\Omega,$

$\gamma=\frac{\eta-\eta_1}{\eta+\eta_1}=0.3.$