Two stationary frictionless pucks are placed on a level surface at an initial distance of 3.0m. The mass of puck 1 is 0.55kg and it has a charge of
+5.0 x 10-4C,
while puck 2 has a mass of 0.25kg and a charge of +3.5 x 10-4C. Find the velocity of each puck after they have moved very far apart.
F1=Gm1m2r2,F_1=\frac{Gm_1m_2}{r^2},F1=r2Gm1m2,
F2=kq1q2r2,F_2=\frac{kq_1q_2}{r^2},F2=r2kq1q2,
p1=m1v1,p_1=m_1v_1,p1=m1v1,
p2=m2v2,p_2=m_2v_2,p2=m2v2,
{(F2−F1)r=m1v122+m2v222p1=p2\begin{cases} (F_2-F_1)r=\frac{m_1v_1^2}{2}+\frac{m_2v_2^2}{2}\\ p_1=p_2 \end{cases}{(F2−F1)r=2m1v12+2m2v22p1=p2
{2kq1q2r−2Gm1m2r=m1v12+m2v22m1v1=m2v2\begin{cases} \frac{2kq_1q_2}{r}-\frac{2Gm_1m_2}{r}=m_1v_1^2+m_2v_2^2 \\ m_1v_1=m_2v_2 \end{cases}{r2kq1q2−r2Gm1m2=m1v12+m2v22m1v1=m2v2
where
v1=2m2(kq1q2−Gm1m2)m1r(m1+m2)v_1=\sqrt{\frac{2m_2(kq_1q_2-Gm_1m_2)}{m_1r(m_1+m_2)}}v1=m1r(m1+m2)2m2(kq1q2−Gm1m2)
v2=2m1(kq1q2−Gm1m2)m2r(m1+m2)v_2=\sqrt{\frac{2m_1(kq_1q_2-Gm_1m_2)}{m_2r(m_1+m_2)}}v2=m2r(m1+m2)2m1(kq1q2−Gm1m2)
v1≈24.4 msv_1\approx 24.4~\frac msv1≈24.4 sm
v2≈53.7 msv_2\approx 53.7~\frac msv2≈53.7 sm
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