Equal charges of 3x10-9 are situated at the three corners of a square of side 5.20 m. Find the potential at the unoccupied corner.
Answer
Potential due to single charge at distance r is given by
"V=\\frac{kq}{r}"
Potential at unoccupied corner can be written as
"V=\\frac{(9\\times10^{9}) (3\\times10^9)}{5.20^2}(1+\\frac{1}{\\sqrt{2}}) =1.7volts"
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