. The potential field π = 2π₯
2π¦π§ β π¦
3
π§ exists in a dielectric medium having π = 2π0 (a) Does V satisfy
Laplace`s equation? (b) calculate the total charge within the unit cube 0 < π₯, π¦, π§ < 1π.
Answer
a) for laplace condition
"\\nabla ^2V=0" ......... eq1
"\\nabla ^2V=\\frac{d^2V}{dx^2}+\\frac{d^2V}{dy^2}+\\frac{d^2V}{dz^2}"
"V=2x^2yz-y^3z"
"\\frac{d^2V}{dx^2}=4yz"
"\\frac{d^2V}{dy^2}=-6yz"
"\\frac{d^2V}{dz^2}=0"
Putting all value in equation 1
"\\nabla ^2V\\ne0"
So this potential does not satisfy.
b) using poission equation
"\\nabla ^2V=-\\frac{\\rho }{\\epsilon}=-2yz"
Charge
"Q=\\int\\rho dv"
Integrate by putting charge density
"Q=\\epsilon_0=8.85\\times10^{-12}C"
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