Answer to Question #154069 in Electricity and Magnetism for Akash

Question

The electric field in free space is given by E= 50cos (10²t+beta x) a_y

1,find the direction of wave propogation

Answer 1

Given, $E=50Cos(10^{2}t+\beta x)a_{y}$

Compare the above equation with the standard equation;

$E=E_{0}Cos(\omega t-\beta x)a_{y}$

So, $E_{0}=50$

Direction of propagation $=-a_{x}$ i.e. $-x$ $direction$