Answer to Question #153599 in Electricity and Magnetism for Nana

Question

The two plates of a capacitor hold +2800 µC and -2800 µC of charge,

respectively, when the potential difference is 930 V. What is the capacitance? 

Answer 1

Answer

According to physics theory

Relationship between charge potential difference and capacitance is given by as below

$C=\frac{Q}{V}=\frac{0.0028}{930}=3\mu F$