Answer to Question #153231 in Electricity and Magnetism for zaina

Question

A capacitor has a capacitance of 4.50 μF. What charge would be stored if the potential difference is 6V?

Answer 1

By definition of a capacitance,

$C= \frac{q}{V}$

$q = C \times V = 4.5 \times 10^{-6} \times 6 = 27 * 10^{-6} C$

$q= 27 \mu C$