Answer
This is question related to equilibrium.
When the acceleration on the ball is zero then force due to gravity and electrostatic force should be equal.
"mg=\\frac{kqq'}{r^2}"
"5\\times9.8=\\frac{9\\times10^9\\times40\\times40\\times10^{-6}}{r^2}"
So distance between charges or height
r=550.60m
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