Answer
Elecric field due to uniformly charged with a constant charge density λ. Is given
"dE=\\frac{2k\\lambda}{r}dr"
Work done is given by
"dW=QdE"
So total work done
"W=\\int^{y_2}_{y_1} Q\\frac{2k\\lambda }{r}dr"
"W=2kQ\\lambda \\ln{ (\\frac {y_2}{y_1})}"
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