Question

An Electron enters perpendicularly into a uniform magnetic field which has a flux density of 0.12T. This results in a magnetic force of 9.6x10-12N on the electron. Calculate the speed of the electron as it enters the magnetic field. [ e=1.6x10-19 C]

Answer 1

$Force=q(v\times B )$

$9.6\times10^{-12}=1.6\times10^{-19}\times v\times0.12$

$v=5 \times 10^8m/s$