How many electrons move through a single 35.0 W headlight? How many electrons pass through it each second
The power of a current
"P=VI"The current
"I=\\frac{P}{V}"Hence, the number of electrons passing through the bulb
"N=\\frac{q}{e}=\\frac{It}{e}=\\frac{Pt}{Ve}""N=\\frac{35.0*1}{220*1.6*10^{-19}}=9.94*10^{17}"
Comments
Leave a comment