Answer to Question #305060 in Electric Circuits for haasggdfnsd

Question

In series circuit, the voltmeter reads 120V. Find what is (a.) the combined resistance (b) the potential differences across the combination (c) the voltage across the 30ꭥ resistor and (d) the current flows through the 10ꭥ resistor?

Answer 1

Solution;

(a)

Combine resistance;

$R_c=R_1+R_2...R_n$

$R_c=3+10=13\Omega$

(b)

Potential difference;

$V=120V$

(c)

Current;

$I=\frac{V}{R}=\frac{120}{13}=9.231A$

$V_3=IR=9.2307×3=27.692V$

d)

Current in 10$\Omega$ is;

$I=I_1=I_2=I_n$

$I_{10}=9.2307A$