Three identical capacitors are connected with a resistor in two different circuits. When they are connected in series, the time constant to charge up this circuit is 0.02s. What is the time constant when they are connected as in parallel?
Explanations & Calculations
"\\qquad\\qquad\n\\begin{aligned}\n\\small C_{equivalent}&=\\small \\frac{C}{3}\\\\\n\\therefore\\quad\\small 0.02\\,s&=\\small R\\frac{C}{3}\\\\\n\\small RC&=\\small 0.06\\,s\n\\end{aligned}"
"\\qquad\\qquad\n\\begin{aligned}\n\\small C_{equivalent}&=\\small 3C\\\\\n\\small \\tau&=\\small R(3C)\\\\\n&=\\small 3\\times0.06\\,s\\\\\n&=\\small 0.18\\,s\n\\end{aligned}"
Comments
Leave a comment