Two point charges Q1 = 44 C and Q2 = -5 C are separated by a distance of 17 cm. Find the electric potential energy of the system
Potential energy is given by: PE = "\\frac{k * Q1 * Q2}{r}"
where Q1, Q2 and r are the charge Q1, charge Q2 and distance between the two charges respectively.
Given, Q1 = 44C
Q2 = -5 C
r = 17 cm = 0.17 meter
and k = 8.99 * "10^9 \\frac{Nm^2}{c^2}"
Therefore, PE = "\\frac{8.99*10^9*44*(-5)}{0.17}"
On solving above, we get,
PE = -1.163 * "10^{13} J"
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