Determine the total capacitance if a 30 pF capacitor is connected in series with 0.03µF capacitor.
Solution;
For capacitors in series;
"\\frac{1}{C_T}=\\frac{1}{C_1}+\\frac{1}{C_2}"
"\\frac{1}{C_T}=\\frac{1}{30\u00d710^{-12}}+\\frac{1}{0.03\u00d710^{-6}}"
"C_T=2.997\u00d710^{-11}F"
Comments
Leave a comment