Question #294844

An electron is accelerated from rest through a potential difference 12 V. What is the change in electric potential energy of the electron? Explain your answer.

Expert's answer

Explanations & Calculations


  • If the potentials of the two points between which the charge moves in are taken to be V1 & V2\small V_1\,\&\,V_2 , then the associated potential energies would be eV1 & eV2\small eV_1\,\&\,eV_2.
  • Then the change in potential energies is just the difference between these two.
  • Therefore, it is as follows

ΔEp=e(V2−V1)=e×12 V=1.6×10−19×C×12 JC−1=1.9×10−18 J\qquad\qquad \begin{aligned} \small \Delta E_p&=\small e(V_2-V_1)\\ &=\small e\times12\,V\\ &=\small 1.6\times10^{-19}\times C\times 12\,JC^{-1}\\ &=\small 1.9\times10^{-18}\,J \end{aligned}

  • You need to know the charge of an electron to continue.
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