Answer to Question #294313 in Electric Circuits for Neenu

Question

A potential difference of 2 volt is applied between points A and B as shown in the network shown in the figure.calculate 1) equivalent resistance of the network across the points A and B 2)the magnitude of currents in the arms AFCEB and AFDEB?

Answer 1

Explanation

a)

• Equivalent resistance for a parallel network is given by

$\qquad\qquad \begin{aligned} \small \frac{1}{R_e}&=\small \frac{1}{R_1}+\frac{1}{R_2}+...\\ \end{aligned}$

• And that for a series network is

$\qquad\qquad \begin{aligned} \small R_e&=\small R_1+R+... \end{aligned}$

b)

• Once the equivalent resistance is calculated, you can apply Ohm's law to calculate the current that flows in each brach

$\qquad\qquad \begin{aligned} \small V&=\small IR_e\\ \small I&=\small \frac{V}{R_e} \end{aligned}$

• However, this may not be an accurate answer as the corresponding figure is not attached.