Since we have a series arrangement for these four resistors, we proceed to find the total power as
"P_T=P_1+P_2+{P_3}+{P_4}"
We substitute to find PT:
"P_T= \\Big( {3000\\,W}+{2600\\,W}+{2200\\,W}+{1800\\,W} \\Big)\n\\\\ \\implies P_T= 9600\\, W"
In conclusion, the power of the resistor is about 9600 W.
Reference:
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