A 0.5 hp, 6-pole induction motor is excited by a 3 –phase, 60 Hz source. If the full-load speed is
1140 rpm, calculate the slip.
We proceed to calculate the speed of the rotor field with respect to the stator and then we can calculate the slip s:
"n_s=\\frac{120f}{p}=\\frac{120(60)}{6}=1200\\,rpm\n\\\\ s=\\cfrac{n_s-n}{n_s}=\\cfrac{1200-1140}{1140}\n\\\\ \\implies s=0.0526=5.26\\, \\%"
In conclusion, under these circumstances, the slip is s=0.0526=5.26 %.
Reference:
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