2021-08-30T20:47:44-04:00
Two charges of -6.25nC and -12.5nC are placed 25cm in a line.
1
2021-09-02T11:45:09-0400
E 1 = k q r 2 = − 9 × 1 0 9 × 12.5 × 1 0 − 9 ( 35 × 1 0 − 2 ) 2 = − 918.36 N / c E_1=\frac{kq}{r^2}=-\frac{9\times10^9\times12.5\times10^{-9}}{({35\times10^{-2}})^2}=-918.36N/c E 1 = r 2 k q = − ( 35 × 1 0 − 2 ) 2 9 × 1 0 9 × 12.5 × 1 0 − 9 = − 918.36 N / c
E 2 = k q r 2 = − 9 × 1 0 9 × 6.5 × 1 0 − 9 ( 10 × 1 0 − 2 ) 2 = − 5850 N / c E_2=\frac{kq}{r^2}=-\frac{9\times10^9\times6.5\times10^{-9}}{({10\times10^{-2}})^2}=-5850N/c E 2 = r 2 k q = − ( 10 × 1 0 − 2 ) 2 9 × 1 0 9 × 6.5 × 1 0 − 9 = − 5850 N / c E = E 1 + E 2 = − 918.36 − 5858 = − 6768.36 N / c E=E_1+E_2=-918.36-5858=-6768.36N/c E = E 1 + E 2 = − 918.36 − 5858 = − 6768.36 N / c
E 1 ′ = k q r 2 = − 9 × 1 0 9 × 12.5 × 1 0 − 9 ( 10 × 1 0 − 2 ) 2 = − 11250 N / c E'_1=\frac{kq}{r^2}=-\frac{9\times10^9\times12.5\times10^{-9}}{({10\times10^{-2}})^2}=-11250N/c E 1 ′ = r 2 k q = − ( 10 × 1 0 − 2 ) 2 9 × 1 0 9 × 12.5 × 1 0 − 9 = − 11250 N / c
E 2 ′ = k q r 2 = − 9 × 1 0 9 × 6.25 × 1 0 − 9 ( 15 × 1 0 − 2 ) 2 = − 2500 N / c E'_2=\frac{kq}{r^2}=-\frac{9\times10^9\times6.25\times10^{-9}}{({15\times10^{-2}})^2}=-2500N/c E 2 ′ = r 2 k q = − ( 15 × 1 0 − 2 ) 2 9 × 1 0 9 × 6.25 × 1 0 − 9 = − 2500 N / c
E ′ = E 1 ′ + E 2 ′ = − 11250 − 2500 = − 13750 N / c E'=E'_1+E'_2=-11250-2500=-13750N/c E ′ = E 1 ′ + E 2 ′ = − 11250 − 2500 = − 13750 N / c
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