Given
Charge of each charge is Q= 4 C
Length of square is L=5×10−3mL=5 \times 10^{-3} mL=5×10−3m
The electric potential at the centre of the square is
V=4kQL2=24kQLV=\frac{4kQ}{\frac{L}{\sqrt 2}}=\sqrt 2\frac{4kQ}{L}V=2L4kQ=2L4kQ
=24(9×109)(4)5×10−3=4.07×1013V=\sqrt 2\frac{4(9\times 10^9)(4 )}{5 \times 10^{-3}}=4.07\times 10^{13} V=25×10−34(9×109)(4)=4.07×1013V
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