Monochromatic light (l = 500 nm) is incident on a soap bubble (n = 1.40). What is the wavelength of the light (in nm) in the bubble film?
The refractive index of air is 1.
The refractive index of the bubble is 1.4.
The relation:
n1λ1=n2λ21×500 nm=1.4×λ2λ2=5001.4=357.1 nmn_1λ_1=n_2λ_2 \\ 1 \times 500 \;nm = 1.4 \times λ_2 \\ λ_2 = \frac{500}{1.4}= 357.1 \;nmn1λ1=n2λ21×500nm=1.4×λ2λ2=1.4500=357.1nm
Answer: 357.1 nm
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