9, IF the engine of a car of mass m is capable of delivering power P, the minimum time needed for the car to accelerate from rest to a speed v is?
Gives
Power =p
Mass=m
Speed=v
Energy change
∆E=12mv2−0∆E=\frac{1}{2}mv^2-0∆E=21mv2−0
∆E=12mv2∆E=\frac{1}{2}mv^2∆E=21mv2
Power(p)=Wt=∆EtPower (p)=\frac{W}{t}=\frac{∆E}{t}Power(p)=tW=t∆E
P=12mv2t=mv22tP=\frac{\frac{1}{2}mv^2}{t}=\frac{mv^2}{2t}P=t21mv2=2tmv2
t=mv22Pt=\frac{mv^2}{2P}t=2Pmv2
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