Given that VS = 3V, VBE = 0.3V, IC = 9mA, and R1 = 1kΩ, calculate the base current of the transistor Q1 using KVL. Also find the current gain (beta ) of the transistor Q1.
We know that load line equation
"V_{BB}=V_{BE}+I_BR_B\\\\V_{BB}=V_S\\\\V_{S}=V_{BE}+I_BR_B"
Put value
"3=0.3+I_B\\times1000"
"2.7=I_B\\times1000"
"I_B=2.7mA"
"I_c=9mA"
"\\beta=\\frac{I_c}{I_B}=\\frac{9\\times10^{-3}}{2.7\\times10^{-3}}=" 3.33
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