Given:
"I=55"
"I'=45"
"R_{\\rm sh}=8\\:\\Omega"
Total current flowing through the both galvanometer and shunt is
"I=I'+I_{\\rm sh}"For parallel connection of the wires
"I'R_A=I_{\\rm sh}R_{\\rm sh}"Combining these equations give
"R_A=\\frac{I-I'}{I'}R_{\\rm sh}=\\frac{55-45}{45}*8\\:\\Omega=1.78\\:\\Omega"
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