Question

Two capacitors of capacitances 1μF and 0.01μF are charged to the same potential,

which will give more intense electric shock if touched? Explain.

Answer 1

Gives

$C_1=1\mu F,C_2=0.1\mu F,$

Both charged same potential mean connected is parallel combination

Potential =V

Charge

$$Q_1=C_1V=1\times10^{-6}\times V=10^{-6} V C$$

$$Q_2=0.01\times10^{-6}\times V =10^{-8}V C$$

$Q_1>Q_2$

Q_1. more intense electric shock if touched Because $Q_1$ Is high camparision $Q_2$